Polynomial Roots: Find Roots Of F(x)=(x+5)³(x-9)²(x+1)

by Felix Dubois 55 views

Hey there, math enthusiasts! Today, we're diving deep into the fascinating world of polynomials, and we're going to tackle a specific problem that'll help us understand how to find the roots of a polynomial function. So, buckle up, grab your calculators (or not, we'll do it the old-fashioned way!), and let's get started!

Understanding Polynomial Roots

Before we jump into the nitty-gritty, let's make sure we're all on the same page about what we mean by the "roots" of a polynomial. Roots, also known as zeros or x-intercepts, are the values of x that make the polynomial function equal to zero. In other words, they're the points where the graph of the polynomial crosses or touches the x-axis. Finding these roots is a fundamental skill in algebra and calculus, and it unlocks a deeper understanding of the polynomial's behavior.

Why are roots so important, you ask? Well, knowing the roots of a polynomial allows us to: fully understand and analyze the function's behavior, including its graph; solve related equations and inequalities; and even model real-world phenomena. Think of it like this: the roots are the key to unlocking the secrets hidden within the polynomial!

Now, the roots of a polynomial is where the polynomial equals zero. Essentially, we're solving the equation f(x) = 0. For a polynomial in factored form, this becomes much easier because we can use the zero-product property, which states that if the product of several factors is zero, then at least one of the factors must be zero. So, if we can factor a polynomial, we can easily find its roots. Factoring the equation properly is the basic key to finding the roots. There are numerous methods and formulas for solving quadratic equations. Some of the methods are factoring, completing the square, quadratic formula. We can determine the nature of the roots using the discriminant. If the discriminant is positive, then the quadratic equation has two distinct real roots. If the discriminant is zero, then the quadratic equation has one real root (a repeated root). If the discriminant is negative, then the quadratic equation has two complex roots.

Our Polynomial: f(x) = (x+5)³(x-9)²(x+1)

Alright, let's meet our star of the show: the polynomial function f(x) = (x+5)³(x-9)²(x+1). Notice anything special about this polynomial? That's right, it's already in factored form! This is a huge win for us because it makes finding the roots a breeze. We don't need to do any fancy factoring tricks; the hard work has already been done.

But before we jump to the solution, let's break down the structure of this polynomial. We have three distinct factors: (x+5)³, (x-9)², and (x+1). Each of these factors contributes to the roots of the polynomial, but they do so in a slightly different way, thanks to the exponents. These exponents tell us about the multiplicity of each root, which is a crucial concept we'll explore in detail shortly. By understanding each root's multiplicity, we will know the behavior of the graph at that root. If the multiplicity is odd, the graph crosses the x-axis at the root. If the multiplicity is even, the graph touches the x-axis and turns around.

Multiplicity is something that makes finding polynomial roots really interesting. It tells us how many times a particular root appears as a solution to the polynomial equation. In simpler terms, it's the exponent of the factor corresponding to that root. For example, in our polynomial, the factor (x+5) is raised to the power of 3, so the root x = -5 has a multiplicity of 3. The factor (x-9) is raised to the power of 2, so the root x = 9 has a multiplicity of 2. And the factor (x+1) has an implicit exponent of 1, so the root x = -1 has a multiplicity of 1. The multiplicity impacts the behavior of the graph of the polynomial at the root. If the multiplicity is odd, the graph crosses the x-axis at that root. If the multiplicity is even, the graph touches the x-axis and turns around.

Finding the Roots: Step-by-Step

Okay, let's get down to business and find the roots of our polynomial, f(x) = (x+5)³(x-9)²(x+1). Remember, we're looking for the values of x that make the function equal to zero. Thanks to the factored form and the zero-product property, this is a straightforward process.

  1. Set each factor equal to zero:

    • (x+5)³ = 0
    • (x-9)² = 0
    • (x+1) = 0
  2. Solve each equation for x:

    • For (x+5)³ = 0, take the cube root of both sides to get x+5 = 0, which means x = -5.
    • For (x-9)² = 0, take the square root of both sides to get x-9 = 0, which means x = 9.
    • For (x+1) = 0, simply subtract 1 from both sides to get x = -1.

And there you have it! We've found the roots of our polynomial. But remember, there's more to the story than just the roots themselves. We also need to consider their multiplicities.

Identifying Multiplicities

Now that we've found the roots, let's talk about their multiplicities. This is where things get interesting, as multiplicity affects the behavior of the polynomial's graph at each root.

  • Root x = -5: The factor (x+5) is raised to the power of 3, so the root x = -5 has a multiplicity of 3. This means that the graph of the polynomial will cross the x-axis at x = -5.
  • Root x = 9: The factor (x-9) is raised to the power of 2, so the root x = 9 has a multiplicity of 2. This means that the graph of the polynomial will touch the x-axis at x = 9 and turn around (it won't cross the axis).
  • Root x = -1: The factor (x+1) has an implicit exponent of 1, so the root x = -1 has a multiplicity of 1. This means that the graph of the polynomial will cross the x-axis at x = -1.

The multiplicity tells us how many times each root appears in the factored form of the polynomial. A root with a multiplicity of n is counted n times. For instance, the root -5, with a multiplicity of 3, is counted three times. This understanding is crucial for sketching the graph of the polynomial accurately.

The Roots and Their Multiplicities: The Solution

Let's summarize our findings. The polynomial f(x) = (x+5)³(x-9)²(x+1) has the following roots:

  • x = -5 with multiplicity 3
  • x = 9 with multiplicity 2
  • x = -1 with multiplicity 1

Knowing the roots and their multiplicities allows us to sketch a rough graph of the polynomial. We know where the graph crosses or touches the x-axis, and we know the general shape of the graph near each root. This is a powerful tool for visualizing polynomial functions and understanding their behavior. The multiplicity of a root also affects how the graph of the polynomial behaves at that x-intercept. If the multiplicity is odd, the graph crosses the x-axis at that point. If the multiplicity is even, the graph touches the x-axis and turns around.

Visualizing the Graph

Now, let's take a moment to visualize what the graph of this polynomial might look like. While we won't draw a precise graph here, we can use our knowledge of the roots and their multiplicities to get a good idea of its shape.

  • At x = -5 (multiplicity 3): The graph crosses the x-axis. Because the multiplicity is odd, the graph will pass straight through the x-axis at this point, like a line cutting through a plane.
  • At x = 9 (multiplicity 2): The graph touches the x-axis and turns around. Since the multiplicity is even, the graph will "bounce" off the x-axis at this point, resembling a parabola's vertex touching the x-axis.
  • At x = -1 (multiplicity 1): The graph crosses the x-axis. Similar to x = -5, the graph will pass straight through the x-axis at this point.

By understanding the multiplicity of each root, we can sketch a more accurate graph of the polynomial function. Sketching a polynomial graph requires the understanding the leading coefficient. The leading coefficient of a polynomial is the coefficient of the term with the highest degree. It determines the end behavior of the graph. If the leading coefficient is positive, the graph rises to the right. If the leading coefficient is negative, the graph falls to the right.

Conclusion

And that's a wrap, folks! We've successfully found the roots of the polynomial f(x) = (x+5)³(x-9)²(x+1) and determined their multiplicities. We've also explored how multiplicity affects the graph of the polynomial, giving us a solid understanding of its behavior. By understanding the relationship between roots, multiplicities, and the graph of a polynomial, we can gain valuable insights into these functions and their applications.

Remember, finding roots is a fundamental skill in mathematics, and it's a stepping stone to more advanced concepts in algebra and calculus. So, keep practicing, keep exploring, and keep those math muscles strong! You are now equipped with the knowledge to tackle similar problems with confidence. Go forth and conquer those polynomials!

Practice Problems

To solidify your understanding, try finding the roots and their multiplicities for the following polynomials:

  1. g(x) = (x-2)⁴(x+3)(x-1)²
  2. h(x) = x(x+4)³(x-5)
  3. j(x) = (2x-1)²(x+7)⁵

Happy root-hunting!